Metamath Proof Explorer


Theorem feq123

Description: Equality theorem for functions. (Contributed by FL, 16-Nov-2008)

Ref Expression
Assertion feq123 ( ( 𝐹 = 𝐺𝐴 = 𝐶𝐵 = 𝐷 ) → ( 𝐹 : 𝐴𝐵𝐺 : 𝐶𝐷 ) )

Proof

Step Hyp Ref Expression
1 simp1 ( ( 𝐹 = 𝐺𝐴 = 𝐶𝐵 = 𝐷 ) → 𝐹 = 𝐺 )
2 simp2 ( ( 𝐹 = 𝐺𝐴 = 𝐶𝐵 = 𝐷 ) → 𝐴 = 𝐶 )
3 simp3 ( ( 𝐹 = 𝐺𝐴 = 𝐶𝐵 = 𝐷 ) → 𝐵 = 𝐷 )
4 1 2 3 feq123d ( ( 𝐹 = 𝐺𝐴 = 𝐶𝐵 = 𝐷 ) → ( 𝐹 : 𝐴𝐵𝐺 : 𝐶𝐷 ) )