Metamath Proof Explorer


Theorem ffn

Description: A mapping is a function with domain. (Contributed by NM, 2-Aug-1994)

Ref Expression
Assertion ffn ( 𝐹 : 𝐴𝐵𝐹 Fn 𝐴 )

Proof

Step Hyp Ref Expression
1 df-f ( 𝐹 : 𝐴𝐵 ↔ ( 𝐹 Fn 𝐴 ∧ ran 𝐹𝐵 ) )
2 1 simplbi ( 𝐹 : 𝐴𝐵𝐹 Fn 𝐴 )