Metamath Proof Explorer


Theorem fin

Description: Mapping into an intersection. (Contributed by NM, 14-Sep-1999) (Proof shortened by Andrew Salmon, 17-Sep-2011)

Ref Expression
Assertion fin ( 𝐹 : 𝐴 ⟶ ( 𝐵𝐶 ) ↔ ( 𝐹 : 𝐴𝐵𝐹 : 𝐴𝐶 ) )

Proof

Step Hyp Ref Expression
1 ssin ( ( ran 𝐹𝐵 ∧ ran 𝐹𝐶 ) ↔ ran 𝐹 ⊆ ( 𝐵𝐶 ) )
2 1 anbi2i ( ( 𝐹 Fn 𝐴 ∧ ( ran 𝐹𝐵 ∧ ran 𝐹𝐶 ) ) ↔ ( 𝐹 Fn 𝐴 ∧ ran 𝐹 ⊆ ( 𝐵𝐶 ) ) )
3 anandi ( ( 𝐹 Fn 𝐴 ∧ ( ran 𝐹𝐵 ∧ ran 𝐹𝐶 ) ) ↔ ( ( 𝐹 Fn 𝐴 ∧ ran 𝐹𝐵 ) ∧ ( 𝐹 Fn 𝐴 ∧ ran 𝐹𝐶 ) ) )
4 2 3 bitr3i ( ( 𝐹 Fn 𝐴 ∧ ran 𝐹 ⊆ ( 𝐵𝐶 ) ) ↔ ( ( 𝐹 Fn 𝐴 ∧ ran 𝐹𝐵 ) ∧ ( 𝐹 Fn 𝐴 ∧ ran 𝐹𝐶 ) ) )
5 df-f ( 𝐹 : 𝐴 ⟶ ( 𝐵𝐶 ) ↔ ( 𝐹 Fn 𝐴 ∧ ran 𝐹 ⊆ ( 𝐵𝐶 ) ) )
6 df-f ( 𝐹 : 𝐴𝐵 ↔ ( 𝐹 Fn 𝐴 ∧ ran 𝐹𝐵 ) )
7 df-f ( 𝐹 : 𝐴𝐶 ↔ ( 𝐹 Fn 𝐴 ∧ ran 𝐹𝐶 ) )
8 6 7 anbi12i ( ( 𝐹 : 𝐴𝐵𝐹 : 𝐴𝐶 ) ↔ ( ( 𝐹 Fn 𝐴 ∧ ran 𝐹𝐵 ) ∧ ( 𝐹 Fn 𝐴 ∧ ran 𝐹𝐶 ) ) )
9 4 5 8 3bitr4i ( 𝐹 : 𝐴 ⟶ ( 𝐵𝐶 ) ↔ ( 𝐹 : 𝐴𝐵𝐹 : 𝐴𝐶 ) )