Metamath Proof Explorer


Theorem fin23lem16

Description: Lemma for fin23 . U ranges over the original set; in particular ran U is a set, although we do not assume here that U is. (Contributed by Stefan O'Rear, 1-Nov-2014)

Ref Expression
Hypothesis fin23lem.a ⊢ 𝑈 = seqω ( ( 𝑖 ∈ ω , 𝑢 ∈ V ↦ if ( ( ( 𝑡 ‘ 𝑖 ) ∩ 𝑢 ) = ∅ , 𝑢 , ( ( 𝑡 ‘ 𝑖 ) ∩ 𝑢 ) ) ) , ∪ ran 𝑡 )
Assertion fin23lem16 ∪ ran 𝑈 = ∪ ran 𝑡

Proof

Step Hyp Ref Expression
1 fin23lem.a ⊢ 𝑈 = seqω ( ( 𝑖 ∈ ω , 𝑢 ∈ V ↦ if ( ( ( 𝑡 ‘ 𝑖 ) ∩ 𝑢 ) = ∅ , 𝑢 , ( ( 𝑡 ‘ 𝑖 ) ∩ 𝑢 ) ) ) , ∪ ran 𝑡 )
2 unissb ⊢ ( ∪ ran 𝑈 ⊆ ∪ ran 𝑡 ↔ ∀ 𝑎 ∈ ran 𝑈 𝑎 ⊆ ∪ ran 𝑡 )
3 1 fnseqom ⊢ 𝑈 Fn ω
4 fvelrnb ⊢ ( 𝑈 Fn ω → ( 𝑎 ∈ ran 𝑈 ↔ ∃ 𝑏 ∈ ω ( 𝑈 ‘ 𝑏 ) = 𝑎 ) )
5 3 4 ax-mp ⊢ ( 𝑎 ∈ ran 𝑈 ↔ ∃ 𝑏 ∈ ω ( 𝑈 ‘ 𝑏 ) = 𝑎 )
6 peano1 ⊢ ∅ ∈ ω
7 0ss ⊢ ∅ ⊆ 𝑏
8 1 fin23lem15 ⊢ ( ( ( 𝑏 ∈ ω ∧ ∅ ∈ ω ) ∧ ∅ ⊆ 𝑏 ) → ( 𝑈 ‘ 𝑏 ) ⊆ ( 𝑈 ‘ ∅ ) )
9 7 8 mpan2 ⊢ ( ( 𝑏 ∈ ω ∧ ∅ ∈ ω ) → ( 𝑈 ‘ 𝑏 ) ⊆ ( 𝑈 ‘ ∅ ) )
10 6 9 mpan2 ⊢ ( 𝑏 ∈ ω → ( 𝑈 ‘ 𝑏 ) ⊆ ( 𝑈 ‘ ∅ ) )
11 vex ⊢ 𝑡 ∈ V
12 11 rnex ⊢ ran 𝑡 ∈ V
13 12 uniex ⊢ ∪ ran 𝑡 ∈ V
14 1 seqom0g ⊢ ( ∪ ran 𝑡 ∈ V → ( 𝑈 ‘ ∅ ) = ∪ ran 𝑡 )
15 13 14 ax-mp ⊢ ( 𝑈 ‘ ∅ ) = ∪ ran 𝑡
16 10 15 sseqtrdi ⊢ ( 𝑏 ∈ ω → ( 𝑈 ‘ 𝑏 ) ⊆ ∪ ran 𝑡 )
17 sseq1 ⊢ ( ( 𝑈 ‘ 𝑏 ) = 𝑎 → ( ( 𝑈 ‘ 𝑏 ) ⊆ ∪ ran 𝑡 ↔ 𝑎 ⊆ ∪ ran 𝑡 ) )
18 16 17 syl5ibcom ⊢ ( 𝑏 ∈ ω → ( ( 𝑈 ‘ 𝑏 ) = 𝑎 → 𝑎 ⊆ ∪ ran 𝑡 ) )
19 18 rexlimiv ⊢ ( ∃ 𝑏 ∈ ω ( 𝑈 ‘ 𝑏 ) = 𝑎 → 𝑎 ⊆ ∪ ran 𝑡 )
20 5 19 sylbi ⊢ ( 𝑎 ∈ ran 𝑈 → 𝑎 ⊆ ∪ ran 𝑡 )
21 2 20 mprgbir ⊢ ∪ ran 𝑈 ⊆ ∪ ran 𝑡
22 fnfvelrn ⊢ ( ( 𝑈 Fn ω ∧ ∅ ∈ ω ) → ( 𝑈 ‘ ∅ ) ∈ ran 𝑈 )
23 3 6 22 mp2an ⊢ ( 𝑈 ‘ ∅ ) ∈ ran 𝑈
24 15 23 eqeltrri ⊢ ∪ ran 𝑡 ∈ ran 𝑈
25 elssuni ⊢ ( ∪ ran 𝑡 ∈ ran 𝑈 → ∪ ran 𝑡 ⊆ ∪ ran 𝑈 )
26 24 25 ax-mp ⊢ ∪ ran 𝑡 ⊆ ∪ ran 𝑈
27 21 26 eqssi ⊢ ∪ ran 𝑈 = ∪ ran 𝑡