Metamath Proof Explorer
Description: A field is a commutative ring. (Contributed by Jeff Madsen, 8-Jun-2010) (Revised by SN, 23-Nov-2024)
|
|
Ref |
Expression |
|
Hypothesis |
fldcrngd.1 |
⊢ ( 𝜑 → 𝑅 ∈ Field ) |
|
Assertion |
fldcrngd |
⊢ ( 𝜑 → 𝑅 ∈ CRing ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
fldcrngd.1 |
⊢ ( 𝜑 → 𝑅 ∈ Field ) |
| 2 |
|
isfld |
⊢ ( 𝑅 ∈ Field ↔ ( 𝑅 ∈ DivRing ∧ 𝑅 ∈ CRing ) ) |
| 3 |
2
|
simprbi |
⊢ ( 𝑅 ∈ Field → 𝑅 ∈ CRing ) |
| 4 |
1 3
|
syl |
⊢ ( 𝜑 → 𝑅 ∈ CRing ) |