Metamath Proof Explorer


Theorem fldextress

Description: Field extension implies a structure restriction relation. (Contributed by Thierry Arnoux, 29-Jul-2023)

Ref Expression
Assertion fldextress ( 𝐸 /FldExt 𝐹 → 𝐹 = ( 𝐸 ↾s ( Base ‘ 𝐹 ) ) )

Proof

Step Hyp Ref Expression
1 fldextfld1 ⊢ ( 𝐸 /FldExt 𝐹 → 𝐸 ∈ Field )
2 fldextfld2 ⊢ ( 𝐸 /FldExt 𝐹 → 𝐹 ∈ Field )
3 brfldext ⊢ ( ( 𝐸 ∈ Field ∧ 𝐹 ∈ Field ) → ( 𝐸 /FldExt 𝐹 ↔ ( 𝐹 = ( 𝐸 ↾s ( Base ‘ 𝐹 ) ) ∧ ( Base ‘ 𝐹 ) ∈ ( SubRing ‘ 𝐸 ) ) ) )
4 1 2 3 syl2anc ⊢ ( 𝐸 /FldExt 𝐹 → ( 𝐸 /FldExt 𝐹 ↔ ( 𝐹 = ( 𝐸 ↾s ( Base ‘ 𝐹 ) ) ∧ ( Base ‘ 𝐹 ) ∈ ( SubRing ‘ 𝐸 ) ) ) )
5 4 ibi ⊢ ( 𝐸 /FldExt 𝐹 → ( 𝐹 = ( 𝐸 ↾s ( Base ‘ 𝐹 ) ) ∧ ( Base ‘ 𝐹 ) ∈ ( SubRing ‘ 𝐸 ) ) )
6 5 simpld ⊢ ( 𝐸 /FldExt 𝐹 → 𝐹 = ( 𝐸 ↾s ( Base ‘ 𝐹 ) ) )