Metamath Proof Explorer
Description: The subfield of a field F generated by the whole base set of F
is F itself. (Contributed by Thierry Arnoux, 11-Jan-2025)
|
|
Ref |
Expression |
|
Hypotheses |
fldgenval.1 |
⊢ 𝐵 = ( Base ‘ 𝐹 ) |
|
|
fldgenval.2 |
⊢ ( 𝜑 → 𝐹 ∈ DivRing ) |
|
Assertion |
fldgenid |
⊢ ( 𝜑 → ( 𝐹 fldGen 𝐵 ) = 𝐵 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
fldgenval.1 |
⊢ 𝐵 = ( Base ‘ 𝐹 ) |
2 |
|
fldgenval.2 |
⊢ ( 𝜑 → 𝐹 ∈ DivRing ) |
3 |
|
ssidd |
⊢ ( 𝜑 → 𝐵 ⊆ 𝐵 ) |
4 |
1 2 3
|
fldgenssv |
⊢ ( 𝜑 → ( 𝐹 fldGen 𝐵 ) ⊆ 𝐵 ) |
5 |
1 2 3
|
fldgenssid |
⊢ ( 𝜑 → 𝐵 ⊆ ( 𝐹 fldGen 𝐵 ) ) |
6 |
4 5
|
eqssd |
⊢ ( 𝜑 → ( 𝐹 fldGen 𝐵 ) = 𝐵 ) |