Metamath Proof Explorer


Theorem fldgenidfld

Description: The subfield generated by a subfield is the subfield itself. (Contributed by Thierry Arnoux, 15-Jan-2025)

Ref Expression
Hypotheses fldgenval.1 𝐵 = ( Base ‘ 𝐹 )
fldgenval.2 ( 𝜑𝐹 ∈ DivRing )
fldgenidfld.s ( 𝜑𝑆 ∈ ( SubDRing ‘ 𝐹 ) )
Assertion fldgenidfld ( 𝜑 → ( 𝐹 fldGen 𝑆 ) = 𝑆 )

Proof

Step Hyp Ref Expression
1 fldgenval.1 𝐵 = ( Base ‘ 𝐹 )
2 fldgenval.2 ( 𝜑𝐹 ∈ DivRing )
3 fldgenidfld.s ( 𝜑𝑆 ∈ ( SubDRing ‘ 𝐹 ) )
4 1 sdrgss ( 𝑆 ∈ ( SubDRing ‘ 𝐹 ) → 𝑆𝐵 )
5 3 4 syl ( 𝜑𝑆𝐵 )
6 1 2 5 fldgenval ( 𝜑 → ( 𝐹 fldGen 𝑆 ) = { 𝑎 ∈ ( SubDRing ‘ 𝐹 ) ∣ 𝑆𝑎 } )
7 intmin ( 𝑆 ∈ ( SubDRing ‘ 𝐹 ) → { 𝑎 ∈ ( SubDRing ‘ 𝐹 ) ∣ 𝑆𝑎 } = 𝑆 )
8 3 7 syl ( 𝜑 { 𝑎 ∈ ( SubDRing ‘ 𝐹 ) ∣ 𝑆𝑎 } = 𝑆 )
9 6 8 eqtrd ( 𝜑 → ( 𝐹 fldGen 𝑆 ) = 𝑆 )