Metamath Proof Explorer


Theorem flidm

Description: The floor function is idempotent. (Contributed by NM, 17-Aug-2008)

Ref Expression
Assertion flidm ( 𝐴 ∈ ℝ → ( ⌊ ‘ ( ⌊ ‘ 𝐴 ) ) = ( ⌊ ‘ 𝐴 ) )

Proof

Step Hyp Ref Expression
1 flcl ( 𝐴 ∈ ℝ → ( ⌊ ‘ 𝐴 ) ∈ ℤ )
2 flid ( ( ⌊ ‘ 𝐴 ) ∈ ℤ → ( ⌊ ‘ ( ⌊ ‘ 𝐴 ) ) = ( ⌊ ‘ 𝐴 ) )
3 1 2 syl ( 𝐴 ∈ ℝ → ( ⌊ ‘ ( ⌊ ‘ 𝐴 ) ) = ( ⌊ ‘ 𝐴 ) )