Metamath Proof Explorer


Theorem fnbrfvb2

Description: Version of fnbrfvb for functions on Cartesian products: function value expressed as a binary relation. See fnbrovb for the form when F is seen as a binary operation. (Contributed by BJ, 15-Feb-2022)

Ref Expression
Assertion fnbrfvb2 ( ( 𝐹 Fn ( 𝑉 × 𝑊 ) ∧ ( 𝐴𝑉𝐵𝑊 ) ) → ( ( 𝐹 ‘ ⟨ 𝐴 , 𝐵 ⟩ ) = 𝐶 ↔ ⟨ 𝐴 , 𝐵𝐹 𝐶 ) )

Proof

Step Hyp Ref Expression
1 opelxpi ( ( 𝐴𝑉𝐵𝑊 ) → ⟨ 𝐴 , 𝐵 ⟩ ∈ ( 𝑉 × 𝑊 ) )
2 fnbrfvb ( ( 𝐹 Fn ( 𝑉 × 𝑊 ) ∧ ⟨ 𝐴 , 𝐵 ⟩ ∈ ( 𝑉 × 𝑊 ) ) → ( ( 𝐹 ‘ ⟨ 𝐴 , 𝐵 ⟩ ) = 𝐶 ↔ ⟨ 𝐴 , 𝐵𝐹 𝐶 ) )
3 1 2 sylan2 ( ( 𝐹 Fn ( 𝑉 × 𝑊 ) ∧ ( 𝐴𝑉𝐵𝑊 ) ) → ( ( 𝐹 ‘ ⟨ 𝐴 , 𝐵 ⟩ ) = 𝐶 ↔ ⟨ 𝐴 , 𝐵𝐹 𝐶 ) )