Metamath Proof Explorer


Theorem fnbrovb

Description: Value of a binary operation expressed as a binary relation. See also fnbrfvb for functions on Cartesian products. (Contributed by BJ, 15-Feb-2022)

Ref Expression
Assertion fnbrovb ( ( 𝐹 Fn ( 𝑉 × 𝑊 ) ∧ ( 𝐴𝑉𝐵𝑊 ) ) → ( ( 𝐴 𝐹 𝐵 ) = 𝐶 ↔ ⟨ 𝐴 , 𝐵𝐹 𝐶 ) )

Proof

Step Hyp Ref Expression
1 df-ov ( 𝐴 𝐹 𝐵 ) = ( 𝐹 ‘ ⟨ 𝐴 , 𝐵 ⟩ )
2 1 eqeq1i ( ( 𝐴 𝐹 𝐵 ) = 𝐶 ↔ ( 𝐹 ‘ ⟨ 𝐴 , 𝐵 ⟩ ) = 𝐶 )
3 fnbrfvb2 ( ( 𝐹 Fn ( 𝑉 × 𝑊 ) ∧ ( 𝐴𝑉𝐵𝑊 ) ) → ( ( 𝐹 ‘ ⟨ 𝐴 , 𝐵 ⟩ ) = 𝐶 ↔ ⟨ 𝐴 , 𝐵𝐹 𝐶 ) )
4 2 3 syl5bb ( ( 𝐹 Fn ( 𝑉 × 𝑊 ) ∧ ( 𝐴𝑉𝐵𝑊 ) ) → ( ( 𝐴 𝐹 𝐵 ) = 𝐶 ↔ ⟨ 𝐴 , 𝐵𝐹 𝐶 ) )