Metamath Proof Explorer


Theorem fndmu

Description: A function has a unique domain. (Contributed by NM, 11-Aug-1994)

Ref Expression
Assertion fndmu ( ( 𝐹 Fn 𝐴𝐹 Fn 𝐵 ) → 𝐴 = 𝐵 )

Proof

Step Hyp Ref Expression
1 fndm ( 𝐹 Fn 𝐴 → dom 𝐹 = 𝐴 )
2 fndm ( 𝐹 Fn 𝐵 → dom 𝐹 = 𝐵 )
3 1 2 sylan9req ( ( 𝐹 Fn 𝐴𝐹 Fn 𝐵 ) → 𝐴 = 𝐵 )