Description: Equality deduction for function predicate with domain. (Contributed by NM, 26-Jun-2011)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | fneq12d.1 | ⊢ ( 𝜑 → 𝐹 = 𝐺 ) | |
| fneq12d.2 | ⊢ ( 𝜑 → 𝐴 = 𝐵 ) | ||
| Assertion | fneq12d | ⊢ ( 𝜑 → ( 𝐹 Fn 𝐴 ↔ 𝐺 Fn 𝐵 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | fneq12d.1 | ⊢ ( 𝜑 → 𝐹 = 𝐺 ) | |
| 2 | fneq12d.2 | ⊢ ( 𝜑 → 𝐴 = 𝐵 ) | |
| 3 | 1 | fneq1d | ⊢ ( 𝜑 → ( 𝐹 Fn 𝐴 ↔ 𝐺 Fn 𝐴 ) ) |
| 4 | 2 | fneq2d | ⊢ ( 𝜑 → ( 𝐺 Fn 𝐴 ↔ 𝐺 Fn 𝐵 ) ) |
| 5 | 3 4 | bitrd | ⊢ ( 𝜑 → ( 𝐹 Fn 𝐴 ↔ 𝐺 Fn 𝐵 ) ) |