Metamath Proof Explorer


Theorem fneu2

Description: There is exactly one value of a function. (Contributed by NM, 7-Nov-1995)

Ref Expression
Assertion fneu2 ( ( 𝐹 Fn 𝐴 ∧ 𝐵 ∈ 𝐴 ) → ∃! 𝑦 ⟨ 𝐵 , 𝑦 ⟩ ∈ 𝐹 )

Proof

Step Hyp Ref Expression
1 fneu ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝐵 ∈ 𝐴 ) → ∃! 𝑦 𝐵 𝐹 𝑦 )
2 df-br ⊢ ( 𝐵 𝐹 𝑦 ↔ ⟨ 𝐵 , 𝑦 ⟩ ∈ 𝐹 )
3 2 eubii ⊢ ( ∃! 𝑦 𝐵 𝐹 𝑦 ↔ ∃! 𝑦 ⟨ 𝐵 , 𝑦 ⟩ ∈ 𝐹 )
4 1 3 sylib ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝐵 ∈ 𝐴 ) → ∃! 𝑦 ⟨ 𝐵 , 𝑦 ⟩ ∈ 𝐹 )