Metamath Proof Explorer
Description: If the domain of a function is a set, the function is a set.
(Contributed by Glauco Siliprandi, 23-Oct-2021)
|
|
Ref |
Expression |
|
Hypotheses |
fnexd.1 |
⊢ ( 𝜑 → 𝐹 Fn 𝐴 ) |
|
|
fnexd.2 |
⊢ ( 𝜑 → 𝐴 ∈ 𝑉 ) |
|
Assertion |
fnexd |
⊢ ( 𝜑 → 𝐹 ∈ V ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
fnexd.1 |
⊢ ( 𝜑 → 𝐹 Fn 𝐴 ) |
2 |
|
fnexd.2 |
⊢ ( 𝜑 → 𝐴 ∈ 𝑉 ) |
3 |
|
fnex |
⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝐴 ∈ 𝑉 ) → 𝐹 ∈ V ) |
4 |
1 2 3
|
syl2anc |
⊢ ( 𝜑 → 𝐹 ∈ V ) |