Metamath Proof Explorer


Theorem fnfco

Description: Composition of two functions. (Contributed by NM, 22-May-2006)

Ref Expression
Assertion fnfco ( ( 𝐹 Fn 𝐴 ∧ 𝐺 : 𝐵 ⟶ 𝐴 ) → ( 𝐹 ∘ 𝐺 ) Fn 𝐵 )

Proof

Step Hyp Ref Expression
1 df-f ⊢ ( 𝐺 : 𝐵 ⟶ 𝐴 ↔ ( 𝐺 Fn 𝐵 ∧ ran 𝐺 ⊆ 𝐴 ) )
2 fnco ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝐺 Fn 𝐵 ∧ ran 𝐺 ⊆ 𝐴 ) → ( 𝐹 ∘ 𝐺 ) Fn 𝐵 )
3 2 3expb ⊢ ( ( 𝐹 Fn 𝐴 ∧ ( 𝐺 Fn 𝐵 ∧ ran 𝐺 ⊆ 𝐴 ) ) → ( 𝐹 ∘ 𝐺 ) Fn 𝐵 )
4 1 3 sylan2b ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝐺 : 𝐵 ⟶ 𝐴 ) → ( 𝐹 ∘ 𝐺 ) Fn 𝐵 )