Metamath Proof Explorer


Theorem fnfvrnss

Description: An upper bound for range determined by function values. (Contributed by NM, 8-Oct-2004)

Ref Expression
Assertion fnfvrnss ( ( 𝐹 Fn 𝐴 ∧ ∀ 𝑥 ∈ 𝐴 ( 𝐹 ‘ 𝑥 ) ∈ 𝐵 ) → ran 𝐹 ⊆ 𝐵 )

Proof

Step Hyp Ref Expression
1 ffnfv ⊢ ( 𝐹 : 𝐴 ⟶ 𝐵 ↔ ( 𝐹 Fn 𝐴 ∧ ∀ 𝑥 ∈ 𝐴 ( 𝐹 ‘ 𝑥 ) ∈ 𝐵 ) )
2 frn ⊢ ( 𝐹 : 𝐴 ⟶ 𝐵 → ran 𝐹 ⊆ 𝐵 )
3 1 2 sylbir ⊢ ( ( 𝐹 Fn 𝐴 ∧ ∀ 𝑥 ∈ 𝐴 ( 𝐹 ‘ 𝑥 ) ∈ 𝐵 ) → ran 𝐹 ⊆ 𝐵 )