Metamath Proof Explorer


Theorem freq12d

Description: Equality deduction for well-founded relations. (Contributed by Stefan O'Rear, 19-Jan-2015) (Proof shortened by Matthew House, 10-Sep-2025)

Ref Expression
Hypotheses freq12d.1 ( 𝜑𝑅 = 𝑆 )
freq12d.2 ( 𝜑𝐴 = 𝐵 )
Assertion freq12d ( 𝜑 → ( 𝑅 Fr 𝐴𝑆 Fr 𝐵 ) )

Proof

Step Hyp Ref Expression
1 freq12d.1 ( 𝜑𝑅 = 𝑆 )
2 freq12d.2 ( 𝜑𝐴 = 𝐵 )
3 freq1 ( 𝑅 = 𝑆 → ( 𝑅 Fr 𝐴𝑆 Fr 𝐴 ) )
4 freq2 ( 𝐴 = 𝐵 → ( 𝑆 Fr 𝐴𝑆 Fr 𝐵 ) )
5 3 4 sylan9bb ( ( 𝑅 = 𝑆𝐴 = 𝐵 ) → ( 𝑅 Fr 𝐴𝑆 Fr 𝐵 ) )
6 1 2 5 syl2anc ( 𝜑 → ( 𝑅 Fr 𝐴𝑆 Fr 𝐵 ) )