Metamath Proof Explorer


Theorem frgrncvvdeqlem1

Description: Lemma 1 for frgrncvvdeq . (Contributed by Alexander van der Vekens, 23-Dec-2017) (Revised by AV, 8-May-2021) (Proof shortened by AV, 12-Feb-2022)

Ref Expression
Hypotheses frgrncvvdeq.v1 ⊢ 𝑉 = ( Vtx ‘ 𝐺 )
frgrncvvdeq.e ⊢ 𝐸 = ( Edg ‘ 𝐺 )
frgrncvvdeq.nx ⊢ 𝐷 = ( 𝐺 NeighbVtx 𝑋 )
frgrncvvdeq.ny ⊢ 𝑁 = ( 𝐺 NeighbVtx 𝑌 )
frgrncvvdeq.x ⊢ ( 𝜑 → 𝑋 ∈ 𝑉 )
frgrncvvdeq.y ⊢ ( 𝜑 → 𝑌 ∈ 𝑉 )
frgrncvvdeq.ne ⊢ ( 𝜑 → 𝑋 ≠ 𝑌 )
frgrncvvdeq.xy ⊢ ( 𝜑 → 𝑌 ∉ 𝐷 )
frgrncvvdeq.f ⊢ ( 𝜑 → 𝐺 ∈ FriendGraph )
frgrncvvdeq.a ⊢ 𝐴 = ( 𝑥 ∈ 𝐷 ↦ ( ℩ 𝑦 ∈ 𝑁 { 𝑥 , 𝑦 } ∈ 𝐸 ) )
Assertion frgrncvvdeqlem1 ( 𝜑 → 𝑋 ∉ 𝑁 )

Proof

Step Hyp Ref Expression
1 frgrncvvdeq.v1 ⊢ 𝑉 = ( Vtx ‘ 𝐺 )
2 frgrncvvdeq.e ⊢ 𝐸 = ( Edg ‘ 𝐺 )
3 frgrncvvdeq.nx ⊢ 𝐷 = ( 𝐺 NeighbVtx 𝑋 )
4 frgrncvvdeq.ny ⊢ 𝑁 = ( 𝐺 NeighbVtx 𝑌 )
5 frgrncvvdeq.x ⊢ ( 𝜑 → 𝑋 ∈ 𝑉 )
6 frgrncvvdeq.y ⊢ ( 𝜑 → 𝑌 ∈ 𝑉 )
7 frgrncvvdeq.ne ⊢ ( 𝜑 → 𝑋 ≠ 𝑌 )
8 frgrncvvdeq.xy ⊢ ( 𝜑 → 𝑌 ∉ 𝐷 )
9 frgrncvvdeq.f ⊢ ( 𝜑 → 𝐺 ∈ FriendGraph )
10 frgrncvvdeq.a ⊢ 𝐴 = ( 𝑥 ∈ 𝐷 ↦ ( ℩ 𝑦 ∈ 𝑁 { 𝑥 , 𝑦 } ∈ 𝐸 ) )
11 df-nel ⊢ ( 𝑌 ∉ 𝐷 ↔ ¬ 𝑌 ∈ 𝐷 )
12 3 eleq2i ⊢ ( 𝑌 ∈ 𝐷 ↔ 𝑌 ∈ ( 𝐺 NeighbVtx 𝑋 ) )
13 11 12 xchbinx ⊢ ( 𝑌 ∉ 𝐷 ↔ ¬ 𝑌 ∈ ( 𝐺 NeighbVtx 𝑋 ) )
14 8 13 sylib ⊢ ( 𝜑 → ¬ 𝑌 ∈ ( 𝐺 NeighbVtx 𝑋 ) )
15 nbgrsym ⊢ ( 𝑋 ∈ ( 𝐺 NeighbVtx 𝑌 ) ↔ 𝑌 ∈ ( 𝐺 NeighbVtx 𝑋 ) )
16 14 15 sylnibr ⊢ ( 𝜑 → ¬ 𝑋 ∈ ( 𝐺 NeighbVtx 𝑌 ) )
17 neleq2 ⊢ ( 𝑁 = ( 𝐺 NeighbVtx 𝑌 ) → ( 𝑋 ∉ 𝑁 ↔ 𝑋 ∉ ( 𝐺 NeighbVtx 𝑌 ) ) )
18 4 17 ax-mp ⊢ ( 𝑋 ∉ 𝑁 ↔ 𝑋 ∉ ( 𝐺 NeighbVtx 𝑌 ) )
19 df-nel ⊢ ( 𝑋 ∉ ( 𝐺 NeighbVtx 𝑌 ) ↔ ¬ 𝑋 ∈ ( 𝐺 NeighbVtx 𝑌 ) )
20 18 19 bitri ⊢ ( 𝑋 ∉ 𝑁 ↔ ¬ 𝑋 ∈ ( 𝐺 NeighbVtx 𝑌 ) )
21 16 20 sylibr ⊢ ( 𝜑 → 𝑋 ∉ 𝑁 )