Metamath Proof Explorer


Theorem frgrncvvdeqlem4

Description: Lemma 4 for frgrncvvdeq . The mapping of neighbors to neighbors is a function. (Contributed by Alexander van der Vekens, 22-Dec-2017) (Revised by AV, 10-May-2021)

Ref Expression
Hypotheses frgrncvvdeq.v1 ⊢ 𝑉 = ( Vtx ‘ 𝐺 )
frgrncvvdeq.e ⊢ 𝐸 = ( Edg ‘ 𝐺 )
frgrncvvdeq.nx ⊢ 𝐷 = ( 𝐺 NeighbVtx 𝑋 )
frgrncvvdeq.ny ⊢ 𝑁 = ( 𝐺 NeighbVtx 𝑌 )
frgrncvvdeq.x ⊢ ( 𝜑 → 𝑋 ∈ 𝑉 )
frgrncvvdeq.y ⊢ ( 𝜑 → 𝑌 ∈ 𝑉 )
frgrncvvdeq.ne ⊢ ( 𝜑 → 𝑋 ≠ 𝑌 )
frgrncvvdeq.xy ⊢ ( 𝜑 → 𝑌 ∉ 𝐷 )
frgrncvvdeq.f ⊢ ( 𝜑 → 𝐺 ∈ FriendGraph )
frgrncvvdeq.a ⊢ 𝐴 = ( 𝑥 ∈ 𝐷 ↦ ( ℩ 𝑦 ∈ 𝑁 { 𝑥 , 𝑦 } ∈ 𝐸 ) )
Assertion frgrncvvdeqlem4 ( 𝜑 → 𝐴 : 𝐷 ⟶ 𝑁 )

Proof

Step Hyp Ref Expression
1 frgrncvvdeq.v1 ⊢ 𝑉 = ( Vtx ‘ 𝐺 )
2 frgrncvvdeq.e ⊢ 𝐸 = ( Edg ‘ 𝐺 )
3 frgrncvvdeq.nx ⊢ 𝐷 = ( 𝐺 NeighbVtx 𝑋 )
4 frgrncvvdeq.ny ⊢ 𝑁 = ( 𝐺 NeighbVtx 𝑌 )
5 frgrncvvdeq.x ⊢ ( 𝜑 → 𝑋 ∈ 𝑉 )
6 frgrncvvdeq.y ⊢ ( 𝜑 → 𝑌 ∈ 𝑉 )
7 frgrncvvdeq.ne ⊢ ( 𝜑 → 𝑋 ≠ 𝑌 )
8 frgrncvvdeq.xy ⊢ ( 𝜑 → 𝑌 ∉ 𝐷 )
9 frgrncvvdeq.f ⊢ ( 𝜑 → 𝐺 ∈ FriendGraph )
10 frgrncvvdeq.a ⊢ 𝐴 = ( 𝑥 ∈ 𝐷 ↦ ( ℩ 𝑦 ∈ 𝑁 { 𝑥 , 𝑦 } ∈ 𝐸 ) )
11 1 2 3 4 5 6 7 8 9 10 frgrncvvdeqlem2 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐷 ) → ∃! 𝑦 ∈ 𝑁 { 𝑥 , 𝑦 } ∈ 𝐸 )
12 riotacl ⊢ ( ∃! 𝑦 ∈ 𝑁 { 𝑥 , 𝑦 } ∈ 𝐸 → ( ℩ 𝑦 ∈ 𝑁 { 𝑥 , 𝑦 } ∈ 𝐸 ) ∈ 𝑁 )
13 11 12 syl ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐷 ) → ( ℩ 𝑦 ∈ 𝑁 { 𝑥 , 𝑦 } ∈ 𝐸 ) ∈ 𝑁 )
14 13 10 fmptd ⊢ ( 𝜑 → 𝐴 : 𝐷 ⟶ 𝑁 )