Metamath Proof Explorer


Theorem frgruhgr0v

Description: Any null graph (without vertices) represented as hypergraph is a friendship graph. (Contributed by AV, 29-Mar-2021)

Ref Expression
Assertion frgruhgr0v ( ( 𝐺 ∈ UHGraph ∧ ( Vtx ‘ 𝐺 ) = ∅ ) → 𝐺 ∈ FriendGraph )

Proof

Step Hyp Ref Expression
1 uhgr0vb ( ( 𝐺 ∈ UHGraph ∧ ( Vtx ‘ 𝐺 ) = ∅ ) → ( 𝐺 ∈ UHGraph ↔ ( iEdg ‘ 𝐺 ) = ∅ ) )
2 1 biimpcd ( 𝐺 ∈ UHGraph → ( ( 𝐺 ∈ UHGraph ∧ ( Vtx ‘ 𝐺 ) = ∅ ) → ( iEdg ‘ 𝐺 ) = ∅ ) )
3 2 anabsi5 ( ( 𝐺 ∈ UHGraph ∧ ( Vtx ‘ 𝐺 ) = ∅ ) → ( iEdg ‘ 𝐺 ) = ∅ )
4 frgr0vb ( ( 𝐺 ∈ UHGraph ∧ ( Vtx ‘ 𝐺 ) = ∅ ∧ ( iEdg ‘ 𝐺 ) = ∅ ) → 𝐺 ∈ FriendGraph )
5 3 4 mpd3an3 ( ( 𝐺 ∈ UHGraph ∧ ( Vtx ‘ 𝐺 ) = ∅ ) → 𝐺 ∈ FriendGraph )