Description: Precomposition with the converse. (Contributed by Jeff Madsen, 2-Sep-2009) (Proof shortened by BJ, 25-Oct-2026)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | funcocnv2 | ⊢ ( Fun 𝐹 → ( 𝐹 ∘ ◡ 𝐹 ) = ( I ↾ ran 𝐹 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | df-fun | ⊢ ( Fun 𝐹 ↔ ( Rel 𝐹 ∧ ( 𝐹 ∘ ◡ 𝐹 ) ⊆ I ) ) | |
| 2 | 1 | simprbi | ⊢ ( Fun 𝐹 → ( 𝐹 ∘ ◡ 𝐹 ) ⊆ I ) |
| 3 | iss | ⊢ ( ( 𝐹 ∘ ◡ 𝐹 ) ⊆ I ↔ ( 𝐹 ∘ ◡ 𝐹 ) = ( I ↾ dom ( 𝐹 ∘ ◡ 𝐹 ) ) ) | |
| 4 | 2 3 | sylib | ⊢ ( Fun 𝐹 → ( 𝐹 ∘ ◡ 𝐹 ) = ( I ↾ dom ( 𝐹 ∘ ◡ 𝐹 ) ) ) |
| 5 | dmcocnv2 | ⊢ dom ( 𝐹 ∘ ◡ 𝐹 ) = ran 𝐹 | |
| 6 | 5 | reseq2i | ⊢ ( I ↾ dom ( 𝐹 ∘ ◡ 𝐹 ) ) = ( I ↾ ran 𝐹 ) |
| 7 | 4 6 | eqtrdi | ⊢ ( Fun 𝐹 → ( 𝐹 ∘ ◡ 𝐹 ) = ( I ↾ ran 𝐹 ) ) |