Metamath Proof Explorer


Theorem funcocnv2

Description: Precomposition with the converse. (Contributed by Jeff Madsen, 2-Sep-2009) (Proof shortened by BJ, 25-Oct-2026)

Ref Expression
Assertion funcocnv2 ( Fun 𝐹 → ( 𝐹 ∘ ◡ 𝐹 ) = ( I ↾ ran 𝐹 ) )

Proof

Step Hyp Ref Expression
1 df-fun ⊢ ( Fun 𝐹 ↔ ( Rel 𝐹 ∧ ( 𝐹 ∘ ◡ 𝐹 ) ⊆ I ) )
2 1 simprbi ⊢ ( Fun 𝐹 → ( 𝐹 ∘ ◡ 𝐹 ) ⊆ I )
3 iss ⊢ ( ( 𝐹 ∘ ◡ 𝐹 ) ⊆ I ↔ ( 𝐹 ∘ ◡ 𝐹 ) = ( I ↾ dom ( 𝐹 ∘ ◡ 𝐹 ) ) )
4 2 3 sylib ⊢ ( Fun 𝐹 → ( 𝐹 ∘ ◡ 𝐹 ) = ( I ↾ dom ( 𝐹 ∘ ◡ 𝐹 ) ) )
5 dmcocnv2 ⊢ dom ( 𝐹 ∘ ◡ 𝐹 ) = ran 𝐹
6 5 reseq2i ⊢ ( I ↾ dom ( 𝐹 ∘ ◡ 𝐹 ) ) = ( I ↾ ran 𝐹 )
7 4 6 eqtrdi ⊢ ( Fun 𝐹 → ( 𝐹 ∘ ◡ 𝐹 ) = ( I ↾ ran 𝐹 ) )