Step |
Hyp |
Ref |
Expression |
1 |
|
imass2 |
⊢ ( ( ◡ 𝐹 “ 𝐴 ) ⊆ 𝐵 → ( 𝐹 “ ( ◡ 𝐹 “ 𝐴 ) ) ⊆ ( 𝐹 “ 𝐵 ) ) |
2 |
|
funimacnv |
⊢ ( Fun 𝐹 → ( 𝐹 “ ( ◡ 𝐹 “ 𝐴 ) ) = ( 𝐴 ∩ ran 𝐹 ) ) |
3 |
|
dfss |
⊢ ( 𝐴 ⊆ ran 𝐹 ↔ 𝐴 = ( 𝐴 ∩ ran 𝐹 ) ) |
4 |
3
|
biimpi |
⊢ ( 𝐴 ⊆ ran 𝐹 → 𝐴 = ( 𝐴 ∩ ran 𝐹 ) ) |
5 |
4
|
eqcomd |
⊢ ( 𝐴 ⊆ ran 𝐹 → ( 𝐴 ∩ ran 𝐹 ) = 𝐴 ) |
6 |
2 5
|
sylan9eq |
⊢ ( ( Fun 𝐹 ∧ 𝐴 ⊆ ran 𝐹 ) → ( 𝐹 “ ( ◡ 𝐹 “ 𝐴 ) ) = 𝐴 ) |
7 |
6
|
sseq1d |
⊢ ( ( Fun 𝐹 ∧ 𝐴 ⊆ ran 𝐹 ) → ( ( 𝐹 “ ( ◡ 𝐹 “ 𝐴 ) ) ⊆ ( 𝐹 “ 𝐵 ) ↔ 𝐴 ⊆ ( 𝐹 “ 𝐵 ) ) ) |
8 |
1 7
|
syl5ib |
⊢ ( ( Fun 𝐹 ∧ 𝐴 ⊆ ran 𝐹 ) → ( ( ◡ 𝐹 “ 𝐴 ) ⊆ 𝐵 → 𝐴 ⊆ ( 𝐹 “ 𝐵 ) ) ) |