Metamath Proof Explorer


Theorem fvco

Description: Value of a function composition. Similar to Exercise 5 of TakeutiZaring p. 28. (Contributed by NM, 22-Apr-2006) (Proof shortened by Mario Carneiro, 26-Dec-2014)

Ref Expression
Assertion fvco ( ( Fun 𝐺𝐴 ∈ dom 𝐺 ) → ( ( 𝐹𝐺 ) ‘ 𝐴 ) = ( 𝐹 ‘ ( 𝐺𝐴 ) ) )

Proof

Step Hyp Ref Expression
1 funfn ( Fun 𝐺𝐺 Fn dom 𝐺 )
2 fvco2 ( ( 𝐺 Fn dom 𝐺𝐴 ∈ dom 𝐺 ) → ( ( 𝐹𝐺 ) ‘ 𝐴 ) = ( 𝐹 ‘ ( 𝐺𝐴 ) ) )
3 1 2 sylanb ( ( Fun 𝐺𝐴 ∈ dom 𝐺 ) → ( ( 𝐹𝐺 ) ‘ 𝐴 ) = ( 𝐹 ‘ ( 𝐺𝐴 ) ) )