Metamath Proof Explorer


Theorem fvfundmfvn0

Description: If the "value of a class" at an argument is not the empty set, then the argument is in the domain of the class and the class restricted to the singleton formed on that argument is a function. (Contributed by Alexander van der Vekens, 26-May-2017) (Proof shortened by BJ, 13-Aug-2022)

Ref Expression
Assertion fvfundmfvn0 ( ( 𝐹𝐴 ) ≠ ∅ → ( 𝐴 ∈ dom 𝐹 ∧ Fun ( 𝐹 ↾ { 𝐴 } ) ) )

Proof

Step Hyp Ref Expression
1 ndmfv ( ¬ 𝐴 ∈ dom 𝐹 → ( 𝐹𝐴 ) = ∅ )
2 1 necon1ai ( ( 𝐹𝐴 ) ≠ ∅ → 𝐴 ∈ dom 𝐹 )
3 nfunsn ( ¬ Fun ( 𝐹 ↾ { 𝐴 } ) → ( 𝐹𝐴 ) = ∅ )
4 3 necon1ai ( ( 𝐹𝐴 ) ≠ ∅ → Fun ( 𝐹 ↾ { 𝐴 } ) )
5 2 4 jca ( ( 𝐹𝐴 ) ≠ ∅ → ( 𝐴 ∈ dom 𝐹 ∧ Fun ( 𝐹 ↾ { 𝐴 } ) ) )