Metamath Proof Explorer


Theorem gcdabs

Description: The gcd of two integers is the same as that of their absolute values. (Contributed by Paul Chapman, 31-Mar-2011) (Proof shortened by SN, 15-Sep-2024)

Ref Expression
Assertion gcdabs ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) → ( ( abs ‘ 𝑀 ) gcd ( abs ‘ 𝑁 ) ) = ( 𝑀 gcd 𝑁 ) )

Proof

Step Hyp Ref Expression
1 zabscl ( 𝑁 ∈ ℤ → ( abs ‘ 𝑁 ) ∈ ℤ )
2 gcdabs1 ( ( 𝑀 ∈ ℤ ∧ ( abs ‘ 𝑁 ) ∈ ℤ ) → ( ( abs ‘ 𝑀 ) gcd ( abs ‘ 𝑁 ) ) = ( 𝑀 gcd ( abs ‘ 𝑁 ) ) )
3 1 2 sylan2 ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) → ( ( abs ‘ 𝑀 ) gcd ( abs ‘ 𝑁 ) ) = ( 𝑀 gcd ( abs ‘ 𝑁 ) ) )
4 gcdabs2 ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) → ( 𝑀 gcd ( abs ‘ 𝑁 ) ) = ( 𝑀 gcd 𝑁 ) )
5 3 4 eqtrd ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) → ( ( abs ‘ 𝑀 ) gcd ( abs ‘ 𝑁 ) ) = ( 𝑀 gcd 𝑁 ) )