Metamath Proof Explorer


Theorem gicsym

Description: Isomorphism is symmetric. (Contributed by Mario Carneiro, 21-Apr-2016)

Ref Expression
Assertion gicsym ( 𝑅 ≃𝑔 𝑆 → 𝑆 ≃𝑔 𝑅 )

Proof

Step Hyp Ref Expression
1 brgic ⊢ ( 𝑅 ≃𝑔 𝑆 ↔ ( 𝑅 GrpIso 𝑆 ) ≠ ∅ )
2 n0 ⊢ ( ( 𝑅 GrpIso 𝑆 ) ≠ ∅ ↔ ∃ 𝑓 𝑓 ∈ ( 𝑅 GrpIso 𝑆 ) )
3 gimcnv ⊢ ( 𝑓 ∈ ( 𝑅 GrpIso 𝑆 ) → ◡ 𝑓 ∈ ( 𝑆 GrpIso 𝑅 ) )
4 brgici ⊢ ( ◡ 𝑓 ∈ ( 𝑆 GrpIso 𝑅 ) → 𝑆 ≃𝑔 𝑅 )
5 3 4 syl ⊢ ( 𝑓 ∈ ( 𝑅 GrpIso 𝑆 ) → 𝑆 ≃𝑔 𝑅 )
6 5 exlimiv ⊢ ( ∃ 𝑓 𝑓 ∈ ( 𝑅 GrpIso 𝑆 ) → 𝑆 ≃𝑔 𝑅 )
7 2 6 sylbi ⊢ ( ( 𝑅 GrpIso 𝑆 ) ≠ ∅ → 𝑆 ≃𝑔 𝑅 )
8 1 7 sylbi ⊢ ( 𝑅 ≃𝑔 𝑆 → 𝑆 ≃𝑔 𝑅 )