Metamath Proof Explorer


Theorem grpodivid

Description: Division of a group member by itself. (Contributed by NM, 15-Feb-2008) (New usage is discouraged.)

Ref Expression
Hypotheses grpdivf.1 𝑋 = ran 𝐺
grpdivf.3 𝐷 = ( /𝑔𝐺 )
grpdivid.3 𝑈 = ( GId ‘ 𝐺 )
Assertion grpodivid ( ( 𝐺 ∈ GrpOp ∧ 𝐴𝑋 ) → ( 𝐴 𝐷 𝐴 ) = 𝑈 )

Proof

Step Hyp Ref Expression
1 grpdivf.1 𝑋 = ran 𝐺
2 grpdivf.3 𝐷 = ( /𝑔𝐺 )
3 grpdivid.3 𝑈 = ( GId ‘ 𝐺 )
4 eqid ( inv ‘ 𝐺 ) = ( inv ‘ 𝐺 )
5 1 4 2 grpodivval ( ( 𝐺 ∈ GrpOp ∧ 𝐴𝑋𝐴𝑋 ) → ( 𝐴 𝐷 𝐴 ) = ( 𝐴 𝐺 ( ( inv ‘ 𝐺 ) ‘ 𝐴 ) ) )
6 5 3anidm23 ( ( 𝐺 ∈ GrpOp ∧ 𝐴𝑋 ) → ( 𝐴 𝐷 𝐴 ) = ( 𝐴 𝐺 ( ( inv ‘ 𝐺 ) ‘ 𝐴 ) ) )
7 1 3 4 grporinv ( ( 𝐺 ∈ GrpOp ∧ 𝐴𝑋 ) → ( 𝐴 𝐺 ( ( inv ‘ 𝐺 ) ‘ 𝐴 ) ) = 𝑈 )
8 6 7 eqtrd ( ( 𝐺 ∈ GrpOp ∧ 𝐴𝑋 ) → ( 𝐴 𝐷 𝐴 ) = 𝑈 )