Metamath Proof Explorer


Theorem gsummptfsf1o

Description: Re-index a finite group sum using a bijection. A version of gsummptf1o expressed using finite support. (Contributed by Thierry Arnoux, 5-Oct-2025)

Ref Expression
Hypotheses gsummptfsf1o.x ⊢ Ⅎ 𝑥 𝐻
gsummptfsf1o.b ⊢ 𝐵 = ( Base ‘ 𝐺 )
gsummptfsf1o.z ⊢ 0 = ( 0g ‘ 𝐺 )
gsummptfsf1o.i ⊢ ( 𝑥 = 𝐸 → 𝐶 = 𝐻 )
gsummptfsf1o.g ⊢ ( 𝜑 → 𝐺 ∈ CMnd )
gsummptfsf1o.1 ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
gsummptfsf1o.a ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ 𝐶 ) finSupp 0 )
gsummptfsf1o.d ⊢ ( 𝜑 → 𝐹 ⊆ 𝐵 )
gsummptfsf1o.f ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → 𝐶 ∈ 𝐹 )
gsummptfsf1o.e ⊢ ( ( 𝜑 ∧ 𝑦 ∈ 𝐷 ) → 𝐸 ∈ 𝐴 )
gsummptfsf1o.h ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → ∃! 𝑦 ∈ 𝐷 𝑥 = 𝐸 )
Assertion gsummptfsf1o ( 𝜑 → ( 𝐺 Σg ( 𝑥 ∈ 𝐴 ↦ 𝐶 ) ) = ( 𝐺 Σg ( 𝑦 ∈ 𝐷 ↦ 𝐻 ) ) )

Proof

Step Hyp Ref Expression
1 gsummptfsf1o.x ⊢ Ⅎ 𝑥 𝐻
2 gsummptfsf1o.b ⊢ 𝐵 = ( Base ‘ 𝐺 )
3 gsummptfsf1o.z ⊢ 0 = ( 0g ‘ 𝐺 )
4 gsummptfsf1o.i ⊢ ( 𝑥 = 𝐸 → 𝐶 = 𝐻 )
5 gsummptfsf1o.g ⊢ ( 𝜑 → 𝐺 ∈ CMnd )
6 gsummptfsf1o.1 ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
7 gsummptfsf1o.a ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ 𝐶 ) finSupp 0 )
8 gsummptfsf1o.d ⊢ ( 𝜑 → 𝐹 ⊆ 𝐵 )
9 gsummptfsf1o.f ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → 𝐶 ∈ 𝐹 )
10 gsummptfsf1o.e ⊢ ( ( 𝜑 ∧ 𝑦 ∈ 𝐷 ) → 𝐸 ∈ 𝐴 )
11 gsummptfsf1o.h ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → ∃! 𝑦 ∈ 𝐷 𝑥 = 𝐸 )
12 8 adantr ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → 𝐹 ⊆ 𝐵 )
13 12 9 sseldd ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → 𝐶 ∈ 𝐵 )
14 13 fmpttd ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ 𝐶 ) : 𝐴 ⟶ 𝐵 )
15 10 ralrimiva ⊢ ( 𝜑 → ∀ 𝑦 ∈ 𝐷 𝐸 ∈ 𝐴 )
16 11 ralrimiva ⊢ ( 𝜑 → ∀ 𝑥 ∈ 𝐴 ∃! 𝑦 ∈ 𝐷 𝑥 = 𝐸 )
17 eqid ⊢ ( 𝑦 ∈ 𝐷 ↦ 𝐸 ) = ( 𝑦 ∈ 𝐷 ↦ 𝐸 )
18 17 f1ompt ⊢ ( ( 𝑦 ∈ 𝐷 ↦ 𝐸 ) : 𝐷 –1-1-onto→ 𝐴 ↔ ( ∀ 𝑦 ∈ 𝐷 𝐸 ∈ 𝐴 ∧ ∀ 𝑥 ∈ 𝐴 ∃! 𝑦 ∈ 𝐷 𝑥 = 𝐸 ) )
19 15 16 18 sylanbrc ⊢ ( 𝜑 → ( 𝑦 ∈ 𝐷 ↦ 𝐸 ) : 𝐷 –1-1-onto→ 𝐴 )
20 2 3 5 6 14 7 19 gsumf1o ⊢ ( 𝜑 → ( 𝐺 Σg ( 𝑥 ∈ 𝐴 ↦ 𝐶 ) ) = ( 𝐺 Σg ( ( 𝑥 ∈ 𝐴 ↦ 𝐶 ) ∘ ( 𝑦 ∈ 𝐷 ↦ 𝐸 ) ) ) )
21 eqidd ⊢ ( 𝜑 → ( 𝑦 ∈ 𝐷 ↦ 𝐸 ) = ( 𝑦 ∈ 𝐷 ↦ 𝐸 ) )
22 eqidd ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐴 ↦ 𝐶 ) = ( 𝑥 ∈ 𝐴 ↦ 𝐶 ) )
23 15 21 22 fmptcos ⊢ ( 𝜑 → ( ( 𝑥 ∈ 𝐴 ↦ 𝐶 ) ∘ ( 𝑦 ∈ 𝐷 ↦ 𝐸 ) ) = ( 𝑦 ∈ 𝐷 ↦ ⦋ 𝐸 / 𝑥 ⦌ 𝐶 ) )
24 nfv ⊢ Ⅎ 𝑥 ( 𝜑 ∧ 𝑦 ∈ 𝐷 )
25 1 a1i ⊢ ( ( 𝜑 ∧ 𝑦 ∈ 𝐷 ) → Ⅎ 𝑥 𝐻 )
26 4 adantl ⊢ ( ( ( 𝜑 ∧ 𝑦 ∈ 𝐷 ) ∧ 𝑥 = 𝐸 ) → 𝐶 = 𝐻 )
27 24 25 10 26 csbiedf ⊢ ( ( 𝜑 ∧ 𝑦 ∈ 𝐷 ) → ⦋ 𝐸 / 𝑥 ⦌ 𝐶 = 𝐻 )
28 27 mpteq2dva ⊢ ( 𝜑 → ( 𝑦 ∈ 𝐷 ↦ ⦋ 𝐸 / 𝑥 ⦌ 𝐶 ) = ( 𝑦 ∈ 𝐷 ↦ 𝐻 ) )
29 23 28 eqtrd ⊢ ( 𝜑 → ( ( 𝑥 ∈ 𝐴 ↦ 𝐶 ) ∘ ( 𝑦 ∈ 𝐷 ↦ 𝐸 ) ) = ( 𝑦 ∈ 𝐷 ↦ 𝐻 ) )
30 29 oveq2d ⊢ ( 𝜑 → ( 𝐺 Σg ( ( 𝑥 ∈ 𝐴 ↦ 𝐶 ) ∘ ( 𝑦 ∈ 𝐷 ↦ 𝐸 ) ) ) = ( 𝐺 Σg ( 𝑦 ∈ 𝐷 ↦ 𝐻 ) ) )
31 20 30 eqtrd ⊢ ( 𝜑 → ( 𝐺 Σg ( 𝑥 ∈ 𝐴 ↦ 𝐶 ) ) = ( 𝐺 Σg ( 𝑦 ∈ 𝐷 ↦ 𝐻 ) ) )