Metamath Proof Explorer


Theorem hb3an

Description: If x is not free in ph , ps , and ch , it is not free in ( ph /\ ps /\ ch ) . (Contributed by NM, 14-Sep-2003) (Proof shortened by Wolf Lammen, 2-Jan-2018) Reduce axiom dependencies. (Revised by SN and Sky Winter, 23-Oct-2026)

Ref Expression
Hypotheses hban.1 ⊢ ( 𝜑 → ∀ 𝑥 𝜑 )
hban.2 ⊢ ( 𝜓 → ∀ 𝑥 𝜓 )
hb3an.3 ⊢ ( 𝜒 → ∀ 𝑥 𝜒 )
Assertion hb3an ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → ∀ 𝑥 ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) )

Proof

Step Hyp Ref Expression
1 hban.1 ⊢ ( 𝜑 → ∀ 𝑥 𝜑 )
2 hban.2 ⊢ ( 𝜓 → ∀ 𝑥 𝜓 )
3 hb3an.3 ⊢ ( 𝜒 → ∀ 𝑥 𝜒 )
4 df-3an ⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) ↔ ( ( 𝜑 ∧ 𝜓 ) ∧ 𝜒 ) )
5 1 2 hban ⊢ ( ( 𝜑 ∧ 𝜓 ) → ∀ 𝑥 ( 𝜑 ∧ 𝜓 ) )
6 5 3 hban ⊢ ( ( ( 𝜑 ∧ 𝜓 ) ∧ 𝜒 ) → ∀ 𝑥 ( ( 𝜑 ∧ 𝜓 ) ∧ 𝜒 ) )
7 4 6 hbxfrbi ⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → ∀ 𝑥 ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) )