Metamath Proof Explorer


Theorem hban

Description: If x is not free in ph and ps , it is not free in ( ph /\ ps ) . (Contributed by NM, 14-May-1993) (Proof shortened by Wolf Lammen, 2-Jan-2018)

Ref Expression
Hypotheses hb.1 ( 𝜑 → ∀ 𝑥 𝜑 )
hb.2 ( 𝜓 → ∀ 𝑥 𝜓 )
Assertion hban ( ( 𝜑𝜓 ) → ∀ 𝑥 ( 𝜑𝜓 ) )

Proof

Step Hyp Ref Expression
1 hb.1 ( 𝜑 → ∀ 𝑥 𝜑 )
2 hb.2 ( 𝜓 → ∀ 𝑥 𝜓 )
3 1 nf5i 𝑥 𝜑
4 2 nf5i 𝑥 𝜓
5 3 4 nfan 𝑥 ( 𝜑𝜓 )
6 5 nf5ri ( ( 𝜑𝜓 ) → ∀ 𝑥 ( 𝜑𝜓 ) )