Metamath Proof Explorer


Theorem hbn

Description: If x is not free in ph , it is not free in -. ph . (Contributed by NM, 10-Jan-1993) (Proof shortened by Wolf Lammen, 17-Dec-2017)

Ref Expression
Hypothesis hbn.1 ( 𝜑 → ∀ 𝑥 𝜑 )
Assertion hbn ( ¬ 𝜑 → ∀ 𝑥 ¬ 𝜑 )

Proof

Step Hyp Ref Expression
1 hbn.1 ( 𝜑 → ∀ 𝑥 𝜑 )
2 hbnt ( ∀ 𝑥 ( 𝜑 → ∀ 𝑥 𝜑 ) → ( ¬ 𝜑 → ∀ 𝑥 ¬ 𝜑 ) )
3 2 1 mpg ( ¬ 𝜑 → ∀ 𝑥 ¬ 𝜑 )