Metamath Proof Explorer


Theorem hbsb

Description: If z is not free in ph , it is not free in [ y / x ] ph when y and z are distinct. Usage of this theorem is discouraged because it depends on ax-13 . Use the weaker hbsbw when possible. (Contributed by NM, 12-Aug-1993) (New usage is discouraged.)

Ref Expression
Hypothesis hbsb.1 ( 𝜑 → ∀ 𝑧 𝜑 )
Assertion hbsb ( [ 𝑦 / 𝑥 ] 𝜑 → ∀ 𝑧 [ 𝑦 / 𝑥 ] 𝜑 )

Proof

Step Hyp Ref Expression
1 hbsb.1 ( 𝜑 → ∀ 𝑧 𝜑 )
2 1 nf5i 𝑧 𝜑
3 2 nfsb 𝑧 [ 𝑦 / 𝑥 ] 𝜑
4 3 nf5ri ( [ 𝑦 / 𝑥 ] 𝜑 → ∀ 𝑧 [ 𝑦 / 𝑥 ] 𝜑 )