Metamath Proof Explorer


Theorem hlcomd

Description: The half-line relation is symmetric. Theorem 6.6 of Schwabhauser p. 44. (Contributed by Thierry Arnoux, 21-Feb-2020)

Ref Expression
Hypotheses ishlg.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
ishlg.i ⊢ 𝐼 = ( Itv ‘ 𝐺 )
ishlg.k ⊢ 𝐾 = ( hlG ‘ 𝐺 )
ishlg.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
ishlg.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
ishlg.c ⊢ ( 𝜑 → 𝐶 ∈ 𝑃 )
ishlg.g ⊢ ( 𝜑 → 𝐺 ∈ 𝑉 )
hlcomd.1 ⊢ ( 𝜑 → 𝐴 ( 𝐾 ‘ 𝐶 ) 𝐵 )
Assertion hlcomd ( 𝜑 → 𝐵 ( 𝐾 ‘ 𝐶 ) 𝐴 )

Proof

Step Hyp Ref Expression
1 ishlg.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
2 ishlg.i ⊢ 𝐼 = ( Itv ‘ 𝐺 )
3 ishlg.k ⊢ 𝐾 = ( hlG ‘ 𝐺 )
4 ishlg.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
5 ishlg.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
6 ishlg.c ⊢ ( 𝜑 → 𝐶 ∈ 𝑃 )
7 ishlg.g ⊢ ( 𝜑 → 𝐺 ∈ 𝑉 )
8 hlcomd.1 ⊢ ( 𝜑 → 𝐴 ( 𝐾 ‘ 𝐶 ) 𝐵 )
9 1 2 3 4 5 6 7 hlcomb ⊢ ( 𝜑 → ( 𝐴 ( 𝐾 ‘ 𝐶 ) 𝐵 ↔ 𝐵 ( 𝐾 ‘ 𝐶 ) 𝐴 ) )
10 8 9 mpbid ⊢ ( 𝜑 → 𝐵 ( 𝐾 ‘ 𝐶 ) 𝐴 )