Metamath Proof Explorer


Theorem hlne2

Description: The half-line relation implies inequality. (Contributed by Thierry Arnoux, 22-Feb-2020)

Ref Expression
Hypotheses ishlg.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
ishlg.i ⊢ 𝐼 = ( Itv ‘ 𝐺 )
ishlg.k ⊢ 𝐾 = ( hlG ‘ 𝐺 )
ishlg.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
ishlg.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
ishlg.c ⊢ ( 𝜑 → 𝐶 ∈ 𝑃 )
ishlg.g ⊢ ( 𝜑 → 𝐺 ∈ 𝑉 )
hlcomd.1 ⊢ ( 𝜑 → 𝐴 ( 𝐾 ‘ 𝐶 ) 𝐵 )
Assertion hlne2 ( 𝜑 → 𝐵 ≠ 𝐶 )

Proof

Step Hyp Ref Expression
1 ishlg.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
2 ishlg.i ⊢ 𝐼 = ( Itv ‘ 𝐺 )
3 ishlg.k ⊢ 𝐾 = ( hlG ‘ 𝐺 )
4 ishlg.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
5 ishlg.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
6 ishlg.c ⊢ ( 𝜑 → 𝐶 ∈ 𝑃 )
7 ishlg.g ⊢ ( 𝜑 → 𝐺 ∈ 𝑉 )
8 hlcomd.1 ⊢ ( 𝜑 → 𝐴 ( 𝐾 ‘ 𝐶 ) 𝐵 )
9 1 2 3 4 5 6 7 ishlg ⊢ ( 𝜑 → ( 𝐴 ( 𝐾 ‘ 𝐶 ) 𝐵 ↔ ( 𝐴 ≠ 𝐶 ∧ 𝐵 ≠ 𝐶 ∧ ( 𝐴 ∈ ( 𝐶 𝐼 𝐵 ) ∨ 𝐵 ∈ ( 𝐶 𝐼 𝐴 ) ) ) ) )
10 8 9 mpbid ⊢ ( 𝜑 → ( 𝐴 ≠ 𝐶 ∧ 𝐵 ≠ 𝐶 ∧ ( 𝐴 ∈ ( 𝐶 𝐼 𝐵 ) ∨ 𝐵 ∈ ( 𝐶 𝐼 𝐴 ) ) ) )
11 10 simp2d ⊢ ( 𝜑 → 𝐵 ≠ 𝐶 )