Metamath Proof Explorer


Theorem hpgcom

Description: The half-plane relation is symmetric. Theorem 9.12 of Schwabhauser p. 72. (Contributed by Thierry Arnoux, 4-Mar-2020)

Ref Expression
Hypotheses hpgid.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
hpgid.i ⊢ 𝐼 = ( Itv ‘ 𝐺 )
hpgid.l ⊢ 𝐿 = ( LineG ‘ 𝐺 )
hpgid.g ⊢ ( 𝜑 → 𝐺 ∈ TarskiG )
hpgid.d ⊢ ( 𝜑 → 𝐷 ∈ ran 𝐿 )
hpgid.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
hpgid.o ⊢ 𝑂 = { ⟨ 𝑎 , 𝑏 ⟩ ∣ ( ( 𝑎 ∈ ( 𝑃 ∖ 𝐷 ) ∧ 𝑏 ∈ ( 𝑃 ∖ 𝐷 ) ) ∧ ∃ 𝑡 ∈ 𝐷 𝑡 ∈ ( 𝑎 𝐼 𝑏 ) ) }
hpgcom.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
hpgcom.1 ⊢ ( 𝜑 → 𝐴 ( ( hpG ‘ 𝐺 ) ‘ 𝐷 ) 𝐵 )
Assertion hpgcom ( 𝜑 → 𝐵 ( ( hpG ‘ 𝐺 ) ‘ 𝐷 ) 𝐴 )

Proof

Step Hyp Ref Expression
1 hpgid.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
2 hpgid.i ⊢ 𝐼 = ( Itv ‘ 𝐺 )
3 hpgid.l ⊢ 𝐿 = ( LineG ‘ 𝐺 )
4 hpgid.g ⊢ ( 𝜑 → 𝐺 ∈ TarskiG )
5 hpgid.d ⊢ ( 𝜑 → 𝐷 ∈ ran 𝐿 )
6 hpgid.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
7 hpgid.o ⊢ 𝑂 = { ⟨ 𝑎 , 𝑏 ⟩ ∣ ( ( 𝑎 ∈ ( 𝑃 ∖ 𝐷 ) ∧ 𝑏 ∈ ( 𝑃 ∖ 𝐷 ) ) ∧ ∃ 𝑡 ∈ 𝐷 𝑡 ∈ ( 𝑎 𝐼 𝑏 ) ) }
8 hpgcom.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
9 hpgcom.1 ⊢ ( 𝜑 → 𝐴 ( ( hpG ‘ 𝐺 ) ‘ 𝐷 ) 𝐵 )
10 ancom ⊢ ( ( 𝐴 𝑂 𝑐 ∧ 𝐵 𝑂 𝑐 ) ↔ ( 𝐵 𝑂 𝑐 ∧ 𝐴 𝑂 𝑐 ) )
11 10 a1i ⊢ ( 𝜑 → ( ( 𝐴 𝑂 𝑐 ∧ 𝐵 𝑂 𝑐 ) ↔ ( 𝐵 𝑂 𝑐 ∧ 𝐴 𝑂 𝑐 ) ) )
12 11 rexbidv ⊢ ( 𝜑 → ( ∃ 𝑐 ∈ 𝑃 ( 𝐴 𝑂 𝑐 ∧ 𝐵 𝑂 𝑐 ) ↔ ∃ 𝑐 ∈ 𝑃 ( 𝐵 𝑂 𝑐 ∧ 𝐴 𝑂 𝑐 ) ) )
13 1 2 3 7 4 5 6 8 hpgbr ⊢ ( 𝜑 → ( 𝐴 ( ( hpG ‘ 𝐺 ) ‘ 𝐷 ) 𝐵 ↔ ∃ 𝑐 ∈ 𝑃 ( 𝐴 𝑂 𝑐 ∧ 𝐵 𝑂 𝑐 ) ) )
14 1 2 3 7 4 5 8 6 hpgbr ⊢ ( 𝜑 → ( 𝐵 ( ( hpG ‘ 𝐺 ) ‘ 𝐷 ) 𝐴 ↔ ∃ 𝑐 ∈ 𝑃 ( 𝐵 𝑂 𝑐 ∧ 𝐴 𝑂 𝑐 ) ) )
15 12 13 14 3bitr4d ⊢ ( 𝜑 → ( 𝐴 ( ( hpG ‘ 𝐺 ) ‘ 𝐷 ) 𝐵 ↔ 𝐵 ( ( hpG ‘ 𝐺 ) ‘ 𝐷 ) 𝐴 ) )
16 9 15 mpbid ⊢ ( 𝜑 → 𝐵 ( ( hpG ‘ 𝐺 ) ‘ 𝐷 ) 𝐴 )