Metamath Proof Explorer


Theorem ifpbi23d

Description: Equivalence deduction for conditional operator for propositions. Convenience theorem for a frequent case. (Contributed by Wolf Lammen, 28-Apr-2024)

Ref Expression
Hypotheses ifpbi23d.1 ( 𝜑 → ( 𝜒𝜂 ) )
ifpbi23d.2 ( 𝜑 → ( 𝜃𝜁 ) )
Assertion ifpbi23d ( 𝜑 → ( if- ( 𝜓 , 𝜒 , 𝜃 ) ↔ if- ( 𝜓 , 𝜂 , 𝜁 ) ) )

Proof

Step Hyp Ref Expression
1 ifpbi23d.1 ( 𝜑 → ( 𝜒𝜂 ) )
2 ifpbi23d.2 ( 𝜑 → ( 𝜃𝜁 ) )
3 biidd ( 𝜑 → ( 𝜓𝜓 ) )
4 3 1 2 ifpbi123d ( 𝜑 → ( if- ( 𝜓 , 𝜒 , 𝜃 ) ↔ if- ( 𝜓 , 𝜂 , 𝜁 ) ) )