Metamath Proof Explorer


Theorem iineq2dv

Description: Equality deduction for indexed intersection. (Contributed by NM, 3-Aug-2004)

Ref Expression
Hypothesis iuneq2dv.1 ( ( 𝜑𝑥𝐴 ) → 𝐵 = 𝐶 )
Assertion iineq2dv ( 𝜑 𝑥𝐴 𝐵 = 𝑥𝐴 𝐶 )

Proof

Step Hyp Ref Expression
1 iuneq2dv.1 ( ( 𝜑𝑥𝐴 ) → 𝐵 = 𝐶 )
2 1 ralrimiva ( 𝜑 → ∀ 𝑥𝐴 𝐵 = 𝐶 )
3 iineq2 ( ∀ 𝑥𝐴 𝐵 = 𝐶 𝑥𝐴 𝐵 = 𝑥𝐴 𝐶 )
4 2 3 syl ( 𝜑 𝑥𝐴 𝐵 = 𝑥𝐴 𝐶 )