Metamath Proof Explorer


Theorem iineq2dv

Description: Equality deduction for indexed intersection. (Contributed by NM, 3-Aug-2004)

Ref Expression
Hypothesis iuneq2dv.1 ( ( 𝜑𝑥𝐴 ) → 𝐵 = 𝐶 )
Assertion iineq2dv ( 𝜑 𝑥𝐴 𝐵 = 𝑥𝐴 𝐶 )

Proof

Step Hyp Ref Expression
1 iuneq2dv.1 ( ( 𝜑𝑥𝐴 ) → 𝐵 = 𝐶 )
2 nfv 𝑥 𝜑
3 2 1 iineq2d ( 𝜑 𝑥𝐴 𝐵 = 𝑥𝐴 𝐶 )