Metamath Proof Explorer


Theorem imass2d

Description: Subset theorem for image. (Contributed by Glauco Siliprandi, 2-Jan-2022)

Ref Expression
Hypothesis imass2d.1 ⊢ ( 𝜑 → 𝐴 ⊆ 𝐵 )
Assertion imass2d ( 𝜑 → ( 𝐶 “ 𝐴 ) ⊆ ( 𝐶 “ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 imass2d.1 ⊢ ( 𝜑 → 𝐴 ⊆ 𝐵 )
2 imass2 ⊢ ( 𝐴 ⊆ 𝐵 → ( 𝐶 “ 𝐴 ) ⊆ ( 𝐶 “ 𝐵 ) )
3 1 2 syl ⊢ ( 𝜑 → ( 𝐶 “ 𝐴 ) ⊆ ( 𝐶 “ 𝐵 ) )