Metamath Proof Explorer


Theorem imdistanda

Description: Distribution of implication with conjunction (deduction version with conjoined antecedent). (Contributed by Jeff Madsen, 19-Jun-2011)

Ref Expression
Hypothesis imdistanda.1 ( ( 𝜑𝜓 ) → ( 𝜒𝜃 ) )
Assertion imdistanda ( 𝜑 → ( ( 𝜓𝜒 ) → ( 𝜓𝜃 ) ) )

Proof

Step Hyp Ref Expression
1 imdistanda.1 ( ( 𝜑𝜓 ) → ( 𝜒𝜃 ) )
2 1 ex ( 𝜑 → ( 𝜓 → ( 𝜒𝜃 ) ) )
3 2 imdistand ( 𝜑 → ( ( 𝜓𝜒 ) → ( 𝜓𝜃 ) ) )