Metamath Proof Explorer
Description: Infer an equivalence from two implications. (Contributed by NM, 6-Mar-2007) (Proof shortened by Wolf Lammen, 27-Sep-2013)
|
|
Ref |
Expression |
|
Hypotheses |
impbid2.1 |
⊢ ( 𝜓 → 𝜒 ) |
|
|
impbid2.2 |
⊢ ( 𝜑 → ( 𝜒 → 𝜓 ) ) |
|
Assertion |
impbid2 |
⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
impbid2.1 |
⊢ ( 𝜓 → 𝜒 ) |
| 2 |
|
impbid2.2 |
⊢ ( 𝜑 → ( 𝜒 → 𝜓 ) ) |
| 3 |
2 1
|
impbid1 |
⊢ ( 𝜑 → ( 𝜒 ↔ 𝜓 ) ) |
| 4 |
3
|
bicomd |
⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) ) |