Metamath Proof Explorer
Description: Deduce an equivalence from two implications. (Contributed by Wolf
Lammen, 12-May-2013)
|
|
Ref |
Expression |
|
Hypotheses |
impbid21d.1 |
⊢ ( 𝜓 → ( 𝜒 → 𝜃 ) ) |
|
|
impbid21d.2 |
⊢ ( 𝜑 → ( 𝜃 → 𝜒 ) ) |
|
Assertion |
impbid21d |
⊢ ( 𝜑 → ( 𝜓 → ( 𝜒 ↔ 𝜃 ) ) ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
impbid21d.1 |
⊢ ( 𝜓 → ( 𝜒 → 𝜃 ) ) |
| 2 |
|
impbid21d.2 |
⊢ ( 𝜑 → ( 𝜃 → 𝜒 ) ) |
| 3 |
|
impbi |
⊢ ( ( 𝜒 → 𝜃 ) → ( ( 𝜃 → 𝜒 ) → ( 𝜒 ↔ 𝜃 ) ) ) |
| 4 |
1 2 3
|
syl2imc |
⊢ ( 𝜑 → ( 𝜓 → ( 𝜒 ↔ 𝜃 ) ) ) |