Metamath Proof Explorer


Theorem inabs3

Description: Absorption law for intersection. (Contributed by Glauco Siliprandi, 17-Aug-2020)

Ref Expression
Assertion inabs3 ( 𝐶 ⊆ 𝐵 → ( ( 𝐴 ∩ 𝐵 ) ∩ 𝐶 ) = ( 𝐴 ∩ 𝐶 ) )

Proof

Step Hyp Ref Expression
1 inass ⊢ ( ( 𝐴 ∩ 𝐵 ) ∩ 𝐶 ) = ( 𝐴 ∩ ( 𝐵 ∩ 𝐶 ) )
2 sseqin2 ⊢ ( 𝐶 ⊆ 𝐵 ↔ ( 𝐵 ∩ 𝐶 ) = 𝐶 )
3 2 biimpi ⊢ ( 𝐶 ⊆ 𝐵 → ( 𝐵 ∩ 𝐶 ) = 𝐶 )
4 3 ineq2d ⊢ ( 𝐶 ⊆ 𝐵 → ( 𝐴 ∩ ( 𝐵 ∩ 𝐶 ) ) = ( 𝐴 ∩ 𝐶 ) )
5 1 4 eqtrid ⊢ ( 𝐶 ⊆ 𝐵 → ( ( 𝐴 ∩ 𝐵 ) ∩ 𝐶 ) = ( 𝐴 ∩ 𝐶 ) )