Metamath Proof Explorer


Theorem incomOLD

Description: Obsolete version of incom as of 12-Dec-2023. Commutative law for intersection of classes. Exercise 7 of TakeutiZaring p. 17. (Contributed by NM, 21-Jun-1993) (New usage is discouraged.) (Proof modification is discouraged.)

Ref Expression
Assertion incomOLD ( 𝐴𝐵 ) = ( 𝐵𝐴 )

Proof

Step Hyp Ref Expression
1 ancom ( ( 𝑥𝐴𝑥𝐵 ) ↔ ( 𝑥𝐵𝑥𝐴 ) )
2 elin ( 𝑥 ∈ ( 𝐴𝐵 ) ↔ ( 𝑥𝐴𝑥𝐵 ) )
3 elin ( 𝑥 ∈ ( 𝐵𝐴 ) ↔ ( 𝑥𝐵𝑥𝐴 ) )
4 1 2 3 3bitr4i ( 𝑥 ∈ ( 𝐴𝐵 ) ↔ 𝑥 ∈ ( 𝐵𝐴 ) )
5 4 eqriv ( 𝐴𝐵 ) = ( 𝐵𝐴 )