Metamath Proof Explorer


Theorem ineq12i

Description: Equality inference for intersection of two classes. (Contributed by NM, 24-Jun-2004) (Proof shortened by Eric Schmidt, 26-Jan-2007)

Ref Expression
Hypotheses ineq1i.1 𝐴 = 𝐵
ineq12i.2 𝐶 = 𝐷
Assertion ineq12i ( 𝐴𝐶 ) = ( 𝐵𝐷 )

Proof

Step Hyp Ref Expression
1 ineq1i.1 𝐴 = 𝐵
2 ineq12i.2 𝐶 = 𝐷
3 ineq12 ( ( 𝐴 = 𝐵𝐶 = 𝐷 ) → ( 𝐴𝐶 ) = ( 𝐵𝐷 ) )
4 1 2 3 mp2an ( 𝐴𝐶 ) = ( 𝐵𝐷 )