Metamath Proof Explorer


Theorem ineq1i

Description: Equality inference for intersection of two classes. (Contributed by NM, 26-Dec-1993)

Ref Expression
Hypothesis ineq1i.1 𝐴 = 𝐵
Assertion ineq1i ( 𝐴𝐶 ) = ( 𝐵𝐶 )

Proof

Step Hyp Ref Expression
1 ineq1i.1 𝐴 = 𝐵
2 ineq1 ( 𝐴 = 𝐵 → ( 𝐴𝐶 ) = ( 𝐵𝐶 ) )
3 1 2 ax-mp ( 𝐴𝐶 ) = ( 𝐵𝐶 )