Metamath Proof Explorer
Description: Equality theorem for intersection of two classes. (Contributed by NM, 26-Dec-1993)
|
|
Ref |
Expression |
|
Assertion |
ineq2 |
⊢ ( 𝐴 = 𝐵 → ( 𝐶 ∩ 𝐴 ) = ( 𝐶 ∩ 𝐵 ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
ineq1 |
⊢ ( 𝐴 = 𝐵 → ( 𝐴 ∩ 𝐶 ) = ( 𝐵 ∩ 𝐶 ) ) |
2 |
|
incom |
⊢ ( 𝐶 ∩ 𝐴 ) = ( 𝐴 ∩ 𝐶 ) |
3 |
|
incom |
⊢ ( 𝐶 ∩ 𝐵 ) = ( 𝐵 ∩ 𝐶 ) |
4 |
1 2 3
|
3eqtr4g |
⊢ ( 𝐴 = 𝐵 → ( 𝐶 ∩ 𝐴 ) = ( 𝐶 ∩ 𝐵 ) ) |