Metamath Proof Explorer


Theorem ineq2i

Description: Equality inference for intersection of two classes. (Contributed by NM, 26-Dec-1993)

Ref Expression
Hypothesis ineq1i.1 𝐴 = 𝐵
Assertion ineq2i ( 𝐶𝐴 ) = ( 𝐶𝐵 )

Proof

Step Hyp Ref Expression
1 ineq1i.1 𝐴 = 𝐵
2 ineq2 ( 𝐴 = 𝐵 → ( 𝐶𝐴 ) = ( 𝐶𝐵 ) )
3 1 2 ax-mp ( 𝐶𝐴 ) = ( 𝐶𝐵 )