Metamath Proof Explorer


Theorem ineqcomi

Description: Two ways of expressing that two classes have a given intersection. Inference form of ineqcom . Disjointness inference when C = (/) . (Contributed by Peter Mazsa, 26-Mar-2017) (Proof shortened by SN, 20-Sep-2024)

Ref Expression
Hypothesis ineqcomi.1 ( 𝐴𝐵 ) = 𝐶
Assertion ineqcomi ( 𝐵𝐴 ) = 𝐶

Proof

Step Hyp Ref Expression
1 ineqcomi.1 ( 𝐴𝐵 ) = 𝐶
2 incom ( 𝐵𝐴 ) = ( 𝐴𝐵 )
3 2 1 eqtri ( 𝐵𝐴 ) = 𝐶