Metamath Proof Explorer
		
		
		
		Description:  The intersection of two open sets of a topology is an open set.
       (Contributed by Glauco Siliprandi, 21-Dec-2024)
		
			
				
					 | 
					 | 
					Ref | 
					Expression | 
				
					
						 | 
						Hypotheses | 
						inopnd.1 | 
						⊢ ( 𝜑  →  𝐽  ∈  Top )  | 
					
					
						 | 
						 | 
						inopnd.2 | 
						⊢ ( 𝜑  →  𝐴  ∈  𝐽 )  | 
					
					
						 | 
						 | 
						inopnd.3 | 
						⊢ ( 𝜑  →  𝐵  ∈  𝐽 )  | 
					
				
					 | 
					Assertion | 
					inopnd | 
					⊢  ( 𝜑  →  ( 𝐴  ∩  𝐵 )  ∈  𝐽 )  | 
				
			
		
		
			
				Proof
				
					
						| Step | 
						Hyp | 
						Ref | 
						Expression | 
					
						
							| 1 | 
							
								
							 | 
							inopnd.1 | 
							⊢ ( 𝜑  →  𝐽  ∈  Top )  | 
						
						
							| 2 | 
							
								
							 | 
							inopnd.2 | 
							⊢ ( 𝜑  →  𝐴  ∈  𝐽 )  | 
						
						
							| 3 | 
							
								
							 | 
							inopnd.3 | 
							⊢ ( 𝜑  →  𝐵  ∈  𝐽 )  | 
						
						
							| 4 | 
							
								
							 | 
							inopn | 
							⊢ ( ( 𝐽  ∈  Top  ∧  𝐴  ∈  𝐽  ∧  𝐵  ∈  𝐽 )  →  ( 𝐴  ∩  𝐵 )  ∈  𝐽 )  | 
						
						
							| 5 | 
							
								1 2 3 4
							 | 
							syl3anc | 
							⊢ ( 𝜑  →  ( 𝐴  ∩  𝐵 )  ∈  𝐽 )  |